Puzzles are dealt in a detailed manner with certain solutions.
Different puzzles are gathered from ShakuntalaDevi's puzzle books.
Keeping in mind certain puzzles for Infosys some reasoning problems are also dealt.
Puzzle name at the top of each problem will give a brief idea regarding the mode of application.
Given that bat and ball together cost Rs.3.75 = 375paise
Let cost of the ball alone be x.
Given cost of the bat is 75p greater than cost of the ball.
Hence cost of the ball = Rs.1.50
=>Cost of the bat = 1.50 + 75 = Rs.2.25
Let B and G represent no.of boys and girls in the original group respectively.
i.e., 2 girls are left for 15 boys who are alone.
B-15 ------------------------->5
5 boys are left out when 15 girls are alone.
=>G/B-15=2/1 --------------------------------(1)
=>G-45/B-15 =1/5 ----------------------------(2)
Assume W as wrong answers and R as correct answers
Given total no.of questions as 100
R+W=100 ---------------------------(1)
Score is calculated by subtracting 2 times wrong answers(2W)
from right answers(R) and given as 85
R-2W=85 -------------------------------(2)
Hence,100-5=95 is the no.of correct answers of Reshma.
Total distance covered by Sneha=1500m
Distance covered by Shilpa=1500*1400/1470=1428.6
Distance to be covered by Shilpa to beat Sushma over full distance 1500-1428.6=71.4m
A the pipes S1,S2,S3 working i.e.,filling the cistern
1/2+1/3-1/5=15+10-6/30=25-6/30=19/30
No.of hours to fill=30/19=1 11\19hours.
What are the next two terms in the sequence?1,1,5,17,61,217.................
What are the next two terms in the sequence?
1,1,5,17,61,217.................
What are the next three terms to the series?
Let x be no.of rupee notes y be no.of 20pcoins.
So,when going for shopping 100x+20y paise were there with Samsrita.
On return she had 100y+20x paise.
Also it is given that she had 1/3 rd of the orginal amount.
Rs.4.80/- is amount spent by Samsrita.
Hence excluding Jan1,1975 they met on every 61st day.
60/2=30 60/3=20 60/4=15 60/5=12 60/6=10
Literary meet for 30 2 day intervals.
Dramatic meet for 20 3 day intervals.
Musical meet for 15 4 day intervals.
Dancing meet for 12 5 day intervals.
Paintng meet for 10 6 day intervals.
First quartr implies 3 months with 90 days.
By counting all the intervals for other groups no.of days in Jan 8,Feb 7,Mar 9.
After the first boy had eaten noof mangoes =x-1
After taking 1/3 rd of remaining it is 2x-2/3
Second boy ate one and tok 1/3 then it is 2(2x-2/3 -1)=4x-10/9
Third boy ate and tok 1/3 as 2(4x-19)/27=8x-38/27
Deducting the rotten one from remaining noogf mangoes left=8x-38/27=8x-765/27
This is divided among the three equally 8x-65/27=3n
Let n be equal to odd number 2b+1
Least value of x for d=0 is 79
Hence 79 is the correct answer.
We have a membership of 12 men and 10 women.In how many ways can the selection be made?
As per the permutations and combinatins concept of mathematics,
out of 12 men one selected as secretary can be done in 12c1 ways
out of 10 women one selected as joint secretary can be done in 10c1 ways
Hence one secrtary and one joint secretary is 12*10=120
Actual span of the plane was 12m
Span of the plane n photograph was 800m
Depth of the plane is 12000m=12cm
Hence,height of the plane when photographed be x
Pramatha and Pranathi went camping.They took their own water in bg plastic bottles.
Pramatha for the first drink 1/2
Pranathi for the first drink 1/2
So Pranathi as per the given information has drunk 1/1024 of water she had in the bottle.
Water left for Pramatha/Water left for Pranathi=1/11 / 1/1024 =1024/11
For permutations the no.of ways to select is npr=n!/(n-r)!
Hence out of 26 letters the possible outcomes are 26p3=26!/23!=15600
Take a good look at the following series.
1-1/3+1/5-1/7+1/9-1/11+1/13....................
From the above informatin,as per equidstant formula of triangle,it is an equilateral triangle.
Planting at all the three corners only 3 can be planted.
The centroid is the middle point placed exactly equidistant from all the corners.
Hence 4 plants can be planted at euqidistant.
Speed of the train=95*5/18 m/sec
Length of the train=96*5/18*3=80m
Length of the tunnel=96*5/18*30=800m
Rajiv gains 18 points than Vinay (50-32=18)
Let W and M be the no.of women and men respectively.
Given W=M+16.................(1)
The weight of the given brick = 4 Kilograms = 4000 grams
It is given that the smaller brick's volume is 4 times smaller than the given one.
The volume of smaller brick = 4 * 4 * 4 = 64 times smaller
The smaller brick's weight = 4000/64 = 62.5 grams
The possible combinations for the given condition are:
The required probability = 2/6 = 1/3
1973,1979,1987,1993,1997,1999.
Given that after walking 26 steps time needed to reach the bottom is
Similarly after walking 34 steps, it needs
18 seconds more to reach the bottom ---(2)
from (1) & (2) it is clear that
for (34-26) steps it took (30-18) seconds.
for 30 seconds -----------how many steps?
Finally Total number of steps = 26 + (steps covered in 30 seconds)=26+20=46 steps.
Compute (100-1)(100-2)(100-3).........................(100+1)(100+2)(100+3)=?
=>(100-1)(100-2)(100-3).........(100-100)(100+1)(100+2)(100+3)
=>(100-1)(100-2)(100-3).........(0)(100+1)(100+2)(100+3)
What do you call a circle which passes through the vertices of of a triangle?
The radius r of the circumscribed circle of the triangle ABC is given by
Here is a sequenc.Can you find the two missing terms?
Hence,for 60 packets to be packed in 60 miutes we need 60 men.
Let us assume that c1 ----------------->first son
c2 ---------------->second son
Suppose that there were x children at the party.
If we distribute the candies in the above mentioned ways,then the resulting expressions
3(x-1)+2---------------------(1)
2x+8-------------------------(2)
Therefore the no.of candies for distribution 2x+8=2*9+8=18+8=26
What is the sum of all numbers between 100 and 1000 which are divisible by 14?
Let us assume that the sum is S
s=14(8+9+10+.....................+71)
s=14(8+71)(71-8+1)/2=7(79)(64)=35392
There fore Total time = 2:00 PM + 3:55 PM + 1:55 PM = 7:50PM
The trains travel at 25 miles per hour.
S434S0, what number must be substituted with to make it divisible by 36?
To be divisible by 36, the number has to be divided by 4 and 9
i.e; S + 4 + 3 + 4 + S + 0 = 9n
The only digit that meets these two condition is 8
Volume of a cube =l pow(2) + b pow(2) + h pow(2).
Here the values of l & b are given.
(diagonal)pow(2) = (length)pow(2) + (breadth)pow(2).
=> (x)pow(2) = 24 pow(2) + 48 pow(2)
Therefore,volume= h pow(2) + x pow(2) =56 pow(2)
Therefore,height of the room=16 ft.
After lunch I returned to Banglore. I drove for 90 minutes.How do you explain it?
90 minutes = 1 hour 30 minutes.
Let us take A,B,C,D are the four equal parts and their sum is equal to 45.
A+2 = B-2 = C*2 = D/2 ----------------(1)
=>A = B-4 ; C = (B-2)/2 ; D = 2(B-2)
=>B-4 + [(B-2)/2] + 2(B-2) = 45
And condition (1) is satisfied.
What is the special about the number 1729?
i .e; (10*10*10) + (9*9*9) = 1729
B + C = Rs 1.10 -------------------(1)
and B – C = Rs 1.00 -------------------(2)
From the equations (1) and (2) it is clear that
90 minutes = 1 hour 30 minutes.
At last I returned to my hotel room, I found that I had only one Rupee remaining in my purse.
How much money did I have in my purse when I started?
Suppose that the money in his purse when he started = x -------------------(1)
For poor boys fund he gave x/2 + 1 Rs/- --------------------------------------(2)
i .e; 1 Rupee more than half the amount he had.
Now he left with [x - (x/2 + 1)] =(x-2)/2 Rs/-
For Orphanage he gave [(x/2 – 1)/2] +2 = (x+6)/4 Rs/- ----------------(3)
Now he left with [(x-2)/2] – [(x+6)/4] = (x-10)/4 Rs/-
For temple building he gave [(x-10)/4]/2 + 3 = (x+14)/8 Rs/- ---------(4)
Now he left with [(x-10)/4] – [(x+14)/8] = (x-34)/8 Rs/-
Finally he had 1 Rupee in his purse.
i .e; Actual amount – Expended amount = 1
:. from (1),(2),(3) and (4) we have
x-{ [ (x+2)/2 ] + [ (x+6)/4 ] + [ (x+14)/8 ] } = 1
:. The original amount in his purse at the beginning = Rs 42/-
Multiply 21978 by 4.Comment about the result?
There fore these two numbers are a pair of paindromes.
1,3,6,10.Name the next three numbers in the series.
The series is +2,+3,+4,-----------------
There fore next three numbers are:
10+5,10+5+6,10+5+6+7 = 15,21,28.
NAME FIVE TERMS OF ANOTHER SERIES
[ex: 10,20,30,40,50. sum=150.]
The first five terms of the series are,there fore 1,2,6,24,120.
Their sum is 153 and are factorials of 1,2,3,4,5 respectively.
1408 hours is actually 8 minutes past 2 PM.
What do you think the pattern is? 6,24,60,120,210,336,………………
The series is 1.2.3, 2.3.4, 3.4.5, 4.5.6, 5.6.7, 6.7.8,----------
The next numbers would be 7.8.9, 8.9.10,-------
(or) 504, 720,-----------------------
He normally meets a train that travels in the same direction at the crossing
Since the cyclist is late by 25 minutes, he starts at 7:25A.M
As his speed is 12 miles per hour, he reaches the crossing at
By 8:30A.M the train is 6 miles ahead of the cyclist
The difference between their timings = 8:30A.M – 8:25A.M = 5 Minutes
The difference between their distances = 6 Miles
Therefore,the train travels 6 miles in 5 minutes
In 1 minute it travels ---------------------?
Suppose that the tree grows x cm each year
Height of the tree at the end of the sixth year = (90 + 6x) cm
Therefore the height of the tree at the end of the twelfth year=(90+12*30)=450cm
She answered , " my age 3 years hence munltiply by 3 and from that subtracted
3 times my age 3 years ago will give you my exact age? How od is the lady?
Age after 3 years wi be (x + 3)
Therefore the age of the lady = 18 years
First day the number of idlis he ate be x
Third day ------------------------- (x+12)
Fourth day ------------------------(x+18)
Fifth day ---------------------------(x+24)
So, on fourth day the number of idlis the man ate were 26.
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